AP EAMCET · PHYSICS · Thermodynamics
A reversible Carnot heat engine converts \(\frac{1}{4}\) th of its input heat into work. When the temperature of the sink is reduced by \(50 \mathrm{~K}\), its efficiency becomes \(33 \frac{1}{3} \%\). The initial temperatures of the source and the sink respectively are
- A 600 K, 550 K
- B 600 K, 450 K
- C 300 K, 150 K
- D 450 K, 350 K
Answer & Solution
Correct Answer
(B) 600 K, 450 K
Step-by-step Solution
Detailed explanation
Given work, \(W=\frac{Q}{4}\) where, \(Q=\) input heat. \( \text { Efficiency, } \eta=\frac{W}{Q}=\frac{Q / 4}{Q} \Rightarrow \eta=\frac{1}{4} \) Also, \(\quad \eta=1-\frac{T_2}{T_1}\) where, \(T_2=\) temperature of sink and \(\quad T_1=\) temperature of source.…
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