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AP EAMCET · PHYSICS · Electrostatics

The velocity acquired by an electron at rest when subjected to a uniform electric field of potential difference 180 V is
(Mass of electron \(=9 \times 10^{-31} \mathrm{~kg}\) and charge of electron \(=1.6 \times 10^{-19} \mathrm{C}\) )

  1. A \(400 \mathrm{~km} \mathrm{~s}^{-1}\)
  2. B \(4000 \mathrm{~km} \mathrm{~s}^{-1}\)
  3. C \(800 \mathrm{~km} \mathrm{~s}^{-1}\)
  4. D \(8000 \mathrm{~km} \mathrm{~s}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(8000 \mathrm{~km} \mathrm{~s}^{-1}\)

Step-by-step Solution

Detailed explanation

\(qV = \frac{1}{2}mv^2\) \(v = \sqrt{\frac{2qV}{m}}\) \(v = \sqrt{\frac{2 \times 1.6 \times 10^{-19} \mathrm{C} \times 180 \mathrm{~V}}{9 \times 10^{-31} \mathrm{~kg}}} = 8 \times 10^6 \mathrm{~m/s} = 8000 \mathrm{~km} \mathrm{~s}^{-1}\)
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