AP EAMCET · Maths · Circle
The normal drawn at \((1,1)\) to the circle \(x^2+y^2-4 x\) \(+6 y-4=0\) is
- A \(4 x+3 y=7\)
- B \(4 x+y=5\)
- C \(x+y=2\)
- D \(4 x-y=3\)
Answer & Solution
Correct Answer
(B) \(4 x+y=5\)
Step-by-step Solution
Detailed explanation
Given circle is \(x^2+y^2-4 x+6 y-4=0\). \(\Rightarrow(g, f)=(-2,3)\) Equation of normal at \(\left(x_1, y_1\right)\) is…
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