AP EAMCET · PHYSICS · Dual Nature of Matter
The threshold frequency of a photosensitive material is \(\mathrm{v}\). When photons of frequency \(2 \mathrm{v}\) incident on the material, photoelectrons are emitted with a maximum linear momentum P. To get photoelectrons with maximum linear momentum \(2 \mathrm{P}\), the frequency of the incident photons is
- A \(2 \mathrm{v}\)
- B \(3 \mathrm{v}\)
- C \(4 \mathrm{v}\)
- D \(5 \mathrm{v}\)
Answer & Solution
Correct Answer
(D) \(5 \mathrm{v}\)
Step-by-step Solution
Detailed explanation
From the photoelectric equation \(\begin{aligned} & h \times 2 v=h v+\frac{P^2}{2 m} \\ & h v=\frac{P^2}{2 m} ... (1)\\ & h v^{\prime}=h v+\frac{(2 p)^2}{2 m}\\ & h v^{\prime}=h v+\frac{4 p^2}{2 m} ... (2) \end{aligned}\) Using the equation (1), we have…
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