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AP EAMCET · PHYSICS · Electromagnetic Waves

The magnetic field of a plane electromagnetic wave is given by B=(400μT)sin4.0x1015 s-1t-xc Average energy density corresponding to the electric field is

  1. A 8×103 J m3
  2. B 31.8×103J m3
  3. C 80×103 J m3
  4. D 3.18×103 J m3
Verified Solution

Answer & Solution

Correct Answer

(B) 31.8×103J m3

Step-by-step Solution

Detailed explanation

Average energy density, Uavg=B022μ0 ⇒Uavg=400×10-622×4π×10-7 ⇒Uavg=16×10-88π×10-7 ⇒Uavg=63.66×10-3 Average energy density corresponding to electric field, U=Uavg2=63.66×10-32 ⇒U=31.8×10-3 J.m-3
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