AP EAMCET · Maths · Three Dimensional Geometry
The equation of the plane passing through the point \(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}\) and perpendicular to the line of intersection of the planes \(\mathbf{r} \cdot(3 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}})=1\) and \(\mathbf{r} \cdot(\hat{\mathbf{i}}+4 \hat{\mathbf{j}}-2 \hat{\mathbf{k}})=2\), is
- A \(\mathbf{r} \cdot(-2 \hat{\mathbf{i}}-5 \hat{\mathbf{j}}+\hat{\mathbf{k}})=0\)
- B \(\mathbf{r} \cdot(\hat{\mathbf{i}}+7 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})=0\)
- C \(\mathbf{r} \cdot(2 \hat{\mathbf{i}}-7 \hat{\mathbf{j}}-13 \hat{\mathbf{k}})=1\)
- D \(\mathbf{r} \cdot(-2 \hat{\mathbf{i}}+7 \hat{\mathbf{j}}+13 \hat{\mathbf{k}})=0\)
Answer & Solution
Correct Answer
(C) \(\mathbf{r} \cdot(2 \hat{\mathbf{i}}-7 \hat{\mathbf{j}}-13 \hat{\mathbf{k}})=1\)
Step-by-step Solution
Detailed explanation
Equation of plane passes through the point \((\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}})=(1,2,-1)\) having direction ratios to normal are \(a, b, c\) is \(a(x-1)+b(y-2)+c(z+1)=0\) \(\because\) Plane (i) is perpendicular to line of intersection of planes…
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