AP EAMCET · PHYSICS · Electromagnetic Induction
In an oscillating \(L C\) circuit, the maximum charge on the capacitor is \(Q\). The charge on the capacitor when the energy is stored equally between the electric and magnetic fields is
- A \(\frac{Q}{2}\)
- B \(\frac{Q}{\sqrt{3}}\)
- C \(Q\)
- D \(\frac{Q}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(D) \(\frac{Q}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
Given, in an oscillating \(L C\) circuit, maximum charge on the capacitor \(=Q\) We know that, total energy stored in the capacitor, \(U=\frac{1}{2} \frac{Q^2}{C}\) \(\therefore\) Energy is equally distributed in a electric field and magnetic field, so the energy stored in the…
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