AP EAMCET · PHYSICS · Electromagnetic Induction
A metallic disc of radius 0.3 m is rotating with a constant angular speed of \(60 \mathrm{rad} \mathrm{s}^{-1}\) in a plane perpendicular to a uniform magnetic field of \(5 \times 10^{-2} \mathrm{~T}\). The emf induced between a point on the rim and centre of the disc is
- A 0.06 V
- B 0.612 V
- C 1.35 V
- D 0.135 V
Answer & Solution
Correct Answer
(D) 0.135 V
Step-by-step Solution
Detailed explanation
\( \mathcal{E} = \frac{1}{2} B \omega R^2 \) \( \mathcal{E} = \frac{1}{2} (5 \times 10^{-2} \, \mathrm{T}) (60 \, \mathrm{rad} \, \mathrm{s}^{-1}) (0.3 \, \mathrm{m})^2 \) \( \mathcal{E} = 0.135 \, \mathrm{V} \)
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