AP EAMCET · PHYSICS · Magnetic Properties of Matter
The deflection produced in a tangent galvanometer, whose coil has a resistance of \(9 \Omega\) is \(30^{\circ}\). The potential difference across the coil is \(4.5 \mathrm{~V}\). If the number of turns in the coil is 10 , the radius of the coil is (Given, \(B_{\mathrm{H}}=3.14 \times 10^{-5} \mathrm{~T}\) )
- A \(2 \sqrt{3} \times 10^{-2} \mathrm{~m}\)
- B \(10 \sqrt{3} \times 10^{-2} \mathrm{~m}\)
- C \(6 \times 10^{-2} \mathrm{~m}\)
- D \(3.5 \times 10^{-2} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(10 \sqrt{3} \times 10^{-2} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
For tangent galvanometer, Deflection, \(\theta=30^{\circ}\) Resistance of coil, \(R=9 \Omega\) Potential difference across coil, \(V=4.5 \mathrm{~V}\) Number of turns in the coil \(\begin{aligned} N & =10 \\ B_H & =3.14 \times 10^{-5} \mathrm{~T} \end{aligned}\) Current flowing…
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