AP EAMCET · PHYSICS · Laws of Motion
The force required to move a body up a rough inclined plane is double the force required to prevent the body from sliding down the plane. If the angle of inclination of the plane is \(60^{\circ}\), then the coefficient of friction is
- A \(\frac{1}{3}\)
- B \(\frac{1}{\sqrt{2}}\)
- C \(\frac{1}{\sqrt{3}}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
According to the question, angle of inclination \(\theta=60^{\circ}\). Now, force of friction, \(f=\mu N=\mu m g \cos \theta\) and net retarding force, \(\left(F_1\right)=m g \sin \theta+f\) \(\therefore\) Net accelerating force down the inclined plane is…
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