AP EAMCET · PHYSICS · Work Power Energy
Length of a simple pendulum is \(1 \mathrm{~m}\). When its bob is at its lowest point its velocity is \(7 \mathrm{~ms}^{-1}\). If the bob leaves its circular path at a height ' \(h\) ' above the centre of the circle, then the value of ' \(h\) ' is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
- A \(0.95 \mathrm{~m}\)
- B \(0.45 \mathrm{~m}\)
- C \(1.25 \mathrm{~m}\)
- D \(0.75 \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(0.95 \mathrm{~m}\)
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