AP EAMCET · Chemistry · Coordination Compounds
The correct order for wavelengths of absorption in the visible region for the following complexes will be
- A \(\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+} < \left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} < \left[\mathrm{Ni}\left(\mathrm{NO}_2\right)_6\right]^{4-}\)
- B \(\left[\mathrm{Ni}\left(\mathrm{NO}_2\right)_6\right]^{4-} < \left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+} < \left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
- C \(\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+} < \left[\mathrm{Ni}\left(\mathrm{NO}_2\right)_6\right]^{4-} < \left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
- D \(\left[\mathrm{Ni}\left(\mathrm{NO}_2\right)_6\right]^{4-} < \left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} < \left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+}\)
Answer & Solution
Correct Answer
(B) \(\left[\mathrm{Ni}\left(\mathrm{NO}_2\right)_6\right]^{4-} < \left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+} < \left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
Step-by-step Solution
Detailed explanation
Complexes, (I) \(\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+}\), (II) \(\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\) and (III) \(\left[\mathrm{Ni}\left(\mathrm{NO}_2\right)_6\right]^{4-}\) are made of \(\mathrm{Ni}^{2+}\) and ligands…
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