AP EAMCET · PHYSICS · Electrostatics
A ball of mass \(1 \mathrm{~g}\) having a charge of \(20 \mu \mathrm{C}\) is tied to one end of a string of length \(0.9 \mathrm{~m}\) can rotate in a vertical plane in a uniform electric field \(100 \mathrm{NC}^{-1}\) directed upwards. The minimum horizontal velocity that must be given to the ball at the lowest position so
that it completes the vertical circle is (Let, \(\mathrm{g}=10 \mathrm{~ms}^{-2}\))
- A \(9 \mathrm{~ms}^{-1}\)
- B \(18 \mathrm{~ms}^{-1}\)
- C \(36 \mathrm{~ms}^{-1}\)
- D \(6 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(D) \(6 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, mass of ball, \(m=1 \mathrm{~g}=\frac{1}{10^3} \mathrm{~kg}\) charge on the ball, \(q=20 \mu C=20 \times 10^{-6} \mathrm{C}\), length of the string centre of one end, \(r=0.9 \mathrm{~m}\) electric field, \(E=100 \mathrm{~N} / \mathrm{C}\) and acceleration due to gravity,…
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