AP EAMCET · PHYSICS · Electromagnetic Induction
The energy stored in a \(50 \mathrm{mH}\) inductor carrying a current of \(4 \mathrm{~A}\) is
- A \(0.4 \mathrm{~J}\)
- B \(4.0 \mathrm{~J}\)
- C \(0.8 \mathrm{~J}\)
- D \(0.04 \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(0.4 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Given, \(\begin{aligned} L=50 \mathrm{mH} & =5 \times 10^{-2} \mathrm{H} \\ I & =4 \mathrm{~A} \end{aligned}\) \(\therefore\) Energy stored in the inductor is given as \(E=\frac{1}{2} L I^2=\frac{1}{2} \times 5 \times 10^{-2} \times 4^2=0.4 \mathrm{~J}\)
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