AP EAMCET · Maths · Indefinite Integration
\(\int \frac{x+\sin x}{1+\cos x} d x\) is equal to
- A \(x \cot \left(\frac{x}{2}\right)+c\)
- B \(\cot \left(\frac{x}{2}\right)+c\)
- C \(\tan \left(\frac{x}{2}\right)+c\)
- D \(x \tan \left(\frac{x}{2}\right)+c\)
Answer & Solution
Correct Answer
(D) \(x \tan \left(\frac{x}{2}\right)+c\)
Step-by-step Solution
Detailed explanation
Let \(I=\int \frac{x+\sin x}{1+\cos x} d x\) \(I=\frac{1}{2} \int\left(x \sec ^2 x / 2\right) d x+\int \tan x / 2 d x\)…
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