AP EAMCET · PHYSICS · Laws of Motion
A block of mass \(5 \mathrm{~kg}\) moving on a rough surface with a velocity of \(4 \mathrm{~ms}^{-1}\) is stopped by the friction in 2 seconds. Then the coefficient of friction between the contact surfaces is
(Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(0.4\)
- B \(0.3\)
- C \(0.5\)
- D \(0.2\)
Answer & Solution
Correct Answer
(D) \(0.2\)
Step-by-step Solution
Detailed explanation
Mass of block, \(\mathrm{m}=5 \mathrm{~kg}\) velocity \(\mathrm{v}=4 \mathrm{~m} / \mathrm{s}\)…
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