AP EAMCET · PHYSICS · Work Power Energy
A block of mass \(50 \mathrm{~kg}\) is pulled with a constant speed of \(4 \mathrm{~ms}^{-1}\) across a horizontal floor by an applied force of \(500 \mathrm{~N}\) directed \(30^{\circ}\) above the horizontal. The rate at which the force does work on the block in watt is
- A \(\frac{2000}{\sqrt{3}}\)
- B \(500 \sqrt{3}\)
- C \(1732\)
- D \(1864\)
Answer & Solution
Correct Answer
(C) \(1732\)
Step-by-step Solution
Detailed explanation
Mass of block, \(m=50 \mathrm{~kg}\), speed of block, \(v=4 \mathrm{~ms}^{-1}\), \(F=500 \mathrm{~N}\) and \(\theta=30^{\circ}\), The rate at which the force does work on the block is equal to power which is given as \(P=\) Force in the horizontal direction \(\times\) velocity…
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