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AP EAMCET · PHYSICS · Units and Dimensions

The energy of \(E\) of a system is function of time \(t\) and is given by \(E(t)=\alpha t-\beta t^3\), where \(\alpha\) and \(\beta\) are constants. The dimensions of \(\alpha\) and \(\beta\) are

  1. A \(\left[\mathrm{ML}^2 T^{-1}\right]\) and \(\left[\mathrm{ML}^2 T\right]\)
  2. B \(\left[\mathrm{LT}^{-1}\right]\) and \([\mathrm{LT}]\)
  3. C \(\left[\mathrm{ML}^2 \mathrm{~T}^{-3}\right]\) and \(\left[\mathrm{ML}^2 \mathrm{~T}^{-5}\right]\)
  4. D \(\left[\mathrm{MLT}^{-1}\right]\) and \([\mathrm{MLT}]\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\left[\mathrm{ML}^2 \mathrm{~T}^{-3}\right]\) and \(\left[\mathrm{ML}^2 \mathrm{~T}^{-5}\right]\)

Step-by-step Solution

Detailed explanation

Energy of the system as a function of time, \(E(t)=\alpha t-\beta t^3\) Where, \(\alpha\) and \(\beta\) are constant. According to principle of homogenity, dimension of \(\alpha t=\) dimension of energy i.e \(\Rightarrow \quad[\alpha][t]=[E]\)…