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AP EAMCET · Maths · Application of Derivatives

The sum of the maximum and the minimum values of \(3 x^4-2 x^3-6 x^2+6 x+4\), in \((0,2)\) is

  1. A 28
  2. B \(\frac{167}{16}\)
  3. C \(\frac{134}{15}\)
  4. D \(\frac{87}{16}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{167}{16}\)

Step-by-step Solution

Detailed explanation

Let a function \(f(x)=3 x^4-2 x^3-6 x^2+6 x+4\) So, \[ \begin{aligned} f^{\prime}(x) & =12 x^3-6 x^2-12 x+6 \\ & =6(x-1)(x+1)(x-1 / 2 \end{aligned} \] For maxima and minima…