AP EAMCET · Maths · Application of Derivatives
The sum of the maximum and the minimum values of \(3 x^4-2 x^3-6 x^2+6 x+4\), in \((0,2)\) is
- A 28
- B \(\frac{167}{16}\)
- C \(\frac{134}{15}\)
- D \(\frac{87}{16}\)
Answer & Solution
Correct Answer
(B) \(\frac{167}{16}\)
Step-by-step Solution
Detailed explanation
Let a function \(f(x)=3 x^4-2 x^3-6 x^2+6 x+4\) So, \[ \begin{aligned} f^{\prime}(x) & =12 x^3-6 x^2-12 x+6 \\ & =6(x-1)(x+1)(x-1 / 2 \end{aligned} \] For maxima and minima…
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