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AP EAMCET · Maths · Properties of Triangles

In \(\triangle \mathrm{ABC}\), if \(\mathrm{A}: \mathrm{B}: \mathrm{C}=5: 1: 6\) then \(a:b:c =\)

  1. A \(\sqrt{2}+1: \sqrt{2}-1: 2 \sqrt{2}\)
  2. B \(\sqrt{3}-1: \sqrt{3}+1: 2 \sqrt{2}\)
  3. C \(\sqrt{3}+1: \sqrt{3}-1: 2 \sqrt{2}\)
  4. D \(\sqrt{3}-1: \sqrt{3}+1: 1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sqrt{3}+1: \sqrt{3}-1: 2 \sqrt{2}\)

Step-by-step Solution

Detailed explanation

\(A: B: C=5: 1: 6 \Rightarrow 5x+x+6x = 180^\circ \Rightarrow 12x = 180^\circ \Rightarrow x = 15^\circ\) \(A = 5 \times 15^\circ = 75^\circ\) \(B = 1 \times 15^\circ = 15^\circ\) \(C = 6 \times 15^\circ = 90^\circ\) \(a:b:c = \sin A : \sin B : \sin C\)…