AP EAMCET · PHYSICS · Alternating Current
The current and emf through an inductance differ by phase by
- A \(\frac{\pi}{4}\)
- B \(\frac{\pi}{2}\)
- C \(\frac{\pi}{3}\)
- D \(\pi\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
We know that, in pure inductive circuit, Alternating voltage, \(V=V_0 \sin \omega t\) and alternating current, \(I=I_0 \sin (\omega t-\pi / 2)\) From the above two equations, it can be seen that alternative current and EMF differ by \(\frac{\pi}{2}\) phase.
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