AP EAMCET · PHYSICS · Capacitance
Eight capacitors each of capacity \(2 \mu \mathrm{~F}\) are arranged as shown in figure. The effective capacitance between \(A\) and \(B\) is
- A \(10 \mu \mathrm{~F}\)
- B \(12 \mu \mathrm{~F}\)
- C \(16 \mu \mathrm{~F}\)
- D \(4 \mu \mathrm{~F}\)
Answer & Solution
Correct Answer
(A) \(10 \mu \mathrm{~F}\)
Step-by-step Solution
Detailed explanation
The effective capacitance between A and B is \(\begin{aligned} & \mathrm{C}_{\mathrm{AB}}=\frac{\mathrm{C}}{2}+2 \mathrm{C}+2 \mathrm{C}+\frac{\mathrm{C}}{2}=5 \mathrm{C} \\ & =5 \times 2=10 \mu \mathrm{~F} \end{aligned}\)
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