AP EAMCET · PHYSICS · Semiconductors
Pure silicon at 300 K has equal electron and hole concentration of \(1.5 \times 10^{16} \mathrm{~m}^{-3}\). If the hole concentration increases to \(3 \times 10^{22} \mathrm{~m}^{-3}\), then electron concentration in the silicon is
- A \(0.75 \times 10^9 \mathrm{~m}^{-3}\)
- B \(750 \mathrm{~m}^{-3}\)
- C \(75 \mathrm{~m}^{-3}\)
- D \(7.5 \times 10^9 \mathrm{~m}^{-3}\)
Answer & Solution
Correct Answer
(D) \(7.5 \times 10^9 \mathrm{~m}^{-3}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{n}_{\mathrm{e}}=\mathrm{n}_{\mathrm{h}}=1.5 \times 10^{16} \mathrm{~m}^{-3}\) \(\therefore \quad\) Number of intrinsic charge carriers, \(\mathrm{n}_{\mathrm{i}}^2=\mathrm{n}_{\mathrm{e}} \mathrm{n}_{\mathrm{h}}=\left(1.5 \times 10^{16}\right)^2\) Again,…
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