AP EAMCET · PHYSICS · Gravitation
Using the data given below, find the height at which a communication satellite can reside. \(\left(G=6.67 \times 10^{-11} \mathrm{~N}-\mathrm{m}^2 \mathrm{~kg}^{-2}, M=5.98 \times 10^{24}\right.\) \(\mathrm{kg}, R=6.4 \times 10^6 \mathrm{~m}\) )
- A \(35850 \mathrm{~km}\)
- B \(3585 \mathrm{~km}\)
- C \(358.5 \mathrm{~km}\)
- D \(35.85 \mathrm{~km}\)
Answer & Solution
Correct Answer
(A) \(35850 \mathrm{~km}\)
Step-by-step Solution
Detailed explanation
Given, \(G=6.67 \times 10^{-11} \mathrm{~N}-\mathrm{m}^2 \mathrm{~kg}^{-2}\) \(M=5.98 \times 10^{24} \mathrm{~kg}, R=6.4 \times 10^6 \mathrm{~m}\) For communication satellite, \(T=24 \mathrm{~h}=24 \times 60 \times 60 \mathrm{~s}=8.64 \times 10^4 \mathrm{~s}\) We know that, time…
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