AP EAMCET · PHYSICS · Wave Optics
The central fringe in the interference pattern obtained in Young's double slit experiment will be a dark fringe when the phase difference between the waves from the two slits is
- A zero
- B \(\frac{\pi}{2}\)
- C \(\pi\)
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(C) \(\pi\)
Step-by-step Solution
Detailed explanation
When the central fringe in the interference pattern in YDSE be a dark fringe, then path difference, will be \(\frac{\lambda}{2}\). i.e., \(\Delta x=\frac{\lambda}{2}\) \(\therefore\) Phase difference,…
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