AP EAMCET · PHYSICS · Capacitance
The capacity of parallel plate condenser is \(5 \mu \mathrm{F}\). When a glass plate is placed between the plates of the condenser, its potential difference reduces to \(1 / 8\) of the original value. The magnitude of relative dielectric constant of glass is
- A 4
- B 6
- C 7
- D 8
Answer & Solution
Correct Answer
(D) 8
Step-by-step Solution
Detailed explanation
Given, \(C=5 \mu \mathrm{F}=5 \times 10^{-6} \mathrm{~F}\) Initial potential \(=V\) When glass plate of dielectric constant \(K\) is introduced between the plates of capacitor, then potential difference is…
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