AP EAMCET · PHYSICS · Electrostatics
Electric potential due to a space is given by \(\phi(x, y, z)=\phi_0 \frac{x_0}{x}\); when \(x_0=5 \mathrm{~m}\) and \(\phi_0=8 V\). Find the electric field at \((10 \mathrm{~m}, 5 \mathrm{~m}, 5 \mathrm{~m})\)
- A \(0.40 \mathrm{Vm}^{-1} \hat{\mathrm{i}}\)
- B \(-0.40 \mathrm{Vm}^{-1} \hat{\mathrm{i}}\)
- C \(4.0 \mathrm{Vm}^{-1} \hat{\mathrm{i}}\)
- D \(-4.0 \mathrm{Vm}^{-1} \hat{\mathrm{i}}\)
Answer & Solution
Correct Answer
(A) \(0.40 \mathrm{Vm}^{-1} \hat{\mathrm{i}}\)
Step-by-step Solution
Detailed explanation
We have \(E=-\frac{d v}{d x}=-\frac{d}{d x} \frac{\left[\phi_0 x_0\right]}{x}=-\phi_0 x_0 \times-\frac{1}{x^2}=\frac{40}{x^2}\) So, \(\left.\mathrm{E}\right|_{(10,5,5)}=\frac{40}{10^2}=0.4 \mathrm{~V} / \mathrm{m}\)
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