AP EAMCET · Chemistry · d and f Block Elements
Select the correct order of radii of the given ions
- A \(\mathrm{Yb}^{3+} < \mathrm{Sm}^{3+} < \mathrm{Dy}^{3+} < \mathrm{Pr}^{3+}\)
- B \(\mathrm{Yb}^{3+} < \mathrm{Dy}^{3+} < \mathrm{Sm}^{3+} < \mathrm{Pr}^{3+}\)
- C \(\mathrm{Pr}^{3+} < \mathrm{Sm}^{3+} < \mathrm{Dy}^{3+} < \mathrm{Yb}^{3+}\)
- D \(\mathrm{Pr}^{3+} < \mathrm{Sm}^{3+} < \mathrm{Yb}^{3+} < \mathrm{Dy}^{3+}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Yb}^{3+} < \mathrm{Dy}^{3+} < \mathrm{Sm}^{3+} < \mathrm{Pr}^{3+}\)
Step-by-step Solution
Detailed explanation
The correct order of ionic radii :- \(\begin{aligned} & { }_{70} \mathrm{Yb}^{3+} < { }_{66} \mathrm{Dy}^{3+} < { }_{62} \mathrm{Sm}^{3+} < { }_{59} \mathrm{Pr}^{3+} \\ & (86 \mathrm{Pm}) \quad(91) \end{aligned}\) This order can be explained on the basis of lanthanide…
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