AP EAMCET · PHYSICS · Current Electricity
The area of cross-section of a copper wire is \(4 \times 10^{-7} \mathrm{~m}^2\) and the electrons per cubic metre in copper is \(8 \times 10^{28}\). If the wire carries a current of 6.4 A, then the drift velocity of the electrons (in \(10^{-3} \mathrm{~m} \mathrm{~s}^{-1}\) ) is
- A \(0.25\)
- B \(2.5\)
- C \(0.125\)
- D \(1.25\)
Answer & Solution
Correct Answer
(D) \(1.25\)
Step-by-step Solution
Detailed explanation
\(v_d = \frac{I}{nAe}\) \(v_d = \frac{6.4}{(8 \times 10^{28}) \times (4 \times 10^{-7}) \times (1.6 \times 10^{-19})}\) \(v_d = 1.25 \times 10^{-3} \mathrm{~m} \mathrm{~s}^{-1}\)
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