AP EAMCET · Maths · Parabola
The distance between the vertex and the focus of the parabola \(x^2-2 x+3 y-2=0\) is
- A \(\frac {4}{5}\)
- B \(\frac {3}{4}\)
- C \(\frac {1}{2}\)
- D \(\frac {5}{6}\)
Answer & Solution
Correct Answer
(B) \(\frac {3}{4}\)
Step-by-step Solution
Detailed explanation
Given equation of parabola \(\begin{aligned} & x^2-2 x+3 y-2=0 \\ & \Rightarrow \quad x^2-2 x+1=-3 y+2+1 \\ & =-3 y+3 \\ & \Rightarrow \quad(x-1)^2=-3(y-1) \end{aligned}\) Distance between the vertex and focus of parabola…
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