AP EAMCET · PHYSICS · Capacitance
Two condensers \(\mathrm{C}_1 \& \mathrm{C}_2\) in a circuit are joined as shown in the figure. The potential of point \(A\) is \(V_1\) and that of point \(B\) is \(V_2\). The potential at point \(D\) will be
- A \(\frac{1}{2}\left(\mathrm{~V}_1+\mathrm{V}_2\right)\)
- B \(\frac{C_2 V_1+C_1 V_2}{C_1+C_2}\)
- C \(\frac{C_1 V_1+C_2 V_2}{C_1+C_2}\)
- D \(\frac{C_2 V_2-C_1 V_2}{C_1+C_2}\)
Answer & Solution
Correct Answer
(C) \(\frac{C_1 V_1+C_2 V_2}{C_1+C_2}\)
Step-by-step Solution
Detailed explanation
In series combination, \(\mathrm{Q}_1=\mathrm{Q}_2\) \(\Rightarrow C_1\left(V_1-V\right)=C_2\left(V-V_2\right)\)…
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