AP EAMCET · PHYSICS · Gravitation
Two masses \(90 \mathrm{~kg}\) and \(160 \mathrm{~kg}\) are separated by a distance of \(5 \mathrm{~m}\). The magnitude of intensity of the gravitational field at a point which is at a distance \(3 \mathrm{~m}\) from the \(90 \mathrm{~kg}\) mass and \(4 \mathrm{~m}\) from the \(160 \mathrm{~kg}\) mass is (Universal gravitational constant, \(\left.G=6.67 \times 10^{-11} \mathrm{~N}-\mathrm{m}^2 \mathrm{~kg}^{-2}\right)\)
- A \(94.3 \times 10^{-10} \mathrm{~N} \mathrm{~kg}^{-1}\)
- B \(9.43 \times 10^{-10} \mathrm{~N} \mathrm{~kg}^{-1}\)
- C \(9.43 \times 10^{-12} \mathrm{~N} \mathrm{~kg}^{-1}\)
- D \(94.3 \times 10^{-12} \mathrm{~N} \mathrm{~kg}^{-1}\)
Answer & Solution
Correct Answer
(B) \(9.43 \times 10^{-10} \mathrm{~N} \mathrm{~kg}^{-1}\)
Step-by-step Solution
Detailed explanation
A system of two masses is shown in the figure, Here, \(m_1=90 \mathrm{~kg}\) and \(m_2=160 \mathrm{~kg}\) Gravitational field intensity due to mass \(A\), \( \mathbf{E}_A=\frac{G M_A}{\mathbf{r}_{C A}^2}=G \frac{90}{\left(3^2\right)}=10 G \hat{\mathbf{r}}_{C A} \) Similarly,…
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