AP EAMCET · Maths · Three Dimensional Geometry
The distance between the orthocentre and circumcentre of the triangle formed by the points \((1,2,3),(3,-1,5)\) and \((4,0,-3)\) is
- A \(\sqrt{\frac{33}{2}}\)
- B \(\sqrt{\frac{31}{2}}\)
- C \(\sqrt{\frac{27}{2}}\)
- D \(\sqrt{\frac{23}{2}}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{\frac{33}{2}}\)
Step-by-step Solution
Detailed explanation
Let \(A=(1,2,3)\) \(\begin{aligned} B & =(3,-1,5) \\ C & =(4,0,-3) \\ D R^{\prime} S \text { of } \overline{A B} & =(2,-3,2) \\ D R^{\prime} \text { ' of } \overline{B C} & =(1,1,-8) \\ D R^{\prime} S \text { of } \overline{A C} & =(3,-2,-6) \end{aligned}\) Here, we noticed that…
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