AP EAMCET · PHYSICS · Oscillations
The amplitude of a simple pendulum is \(10 \mathrm{~cm}\). When the pendulum is at a displacement of \(4 \mathrm{~cm}\) from the mean position, the ratio of kinetic and potential energies at that point is
- A \(5.25\)
- B \(2.5\)
- C \(4.5\)
- D \(7.5\)
Answer & Solution
Correct Answer
(A) \(5.25\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { } \mathrm{K} \cdot \mathrm{E}=\frac{1}{2} m v^2=\frac{1}{2} m \omega^2\left(A^2-x^2\right) \\ & \mathrm{P} . \mathrm{E}=\frac{1}{2} k x^2=\frac{1}{2} m \omega^2 x^2 \end{aligned}\) Therefore, the ratio…
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