AP EAMCET · PHYSICS · Mechanical Properties of Fluids
The radius of cross-section of the cylindrical tube of a spray pump is 2 cm . One end of the pump has 50 fine holes each of radius 0.4 mm . If the speed of flow of the liquid inside the tube is \(0.04 \mathrm{~ms}^{-1}\), the speed of ejection of the liquid from the holes is
- A \(6 \mathrm{~ms}^{-1}\)
- B \(2 \mathrm{~ms}^{-1}\)
- C \(4 \mathrm{~ms}^{-1}\)
- D \(3 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(B) \(2 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
\(r_1=2 \mathrm{~cm}, r_2=0.04 \mathrm{~cm}, v_1=0.04 \mathrm{~ms}^{-1}\) By equation of continuity, \(A_1 v_1=50 A_2 v_2 \Rightarrow \pi(2)^2 \times 0.04=50 \times \pi(0.04)^2 \times v_2\) \(\therefore \quad \mathrm{v}_2=2 \mathrm{~ms}^{-1}\)
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