AP EAMCET · Chemistry · States of Matter
At \(T(K)\) and pressure \(P\), the diffusion rate of an ideal gas is \(120 \mathrm{~mL} \mathrm{~min}^{-1}\). What is the time taken (in sec.) for \(3000 \mathrm{~mL}\) of this gas for diffusion at same temperature and pressure?
- A \(25\)
- B \(1500\)
- C \(250\)
- D \(150\)
Answer & Solution
Correct Answer
(B) \(1500\)
Step-by-step Solution
Detailed explanation
Diffusion rate \(=120 \mathrm{~mL}\) in one minute. \(\Rightarrow\) Time required for the diffusion of \(3000 \mathrm{~mL}\) will be :- \(\mathrm{t}=\frac{3000}{120}=25 \text { minutes }=25 \times 60=1500 \text { seconds. }\)
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