AP EAMCET · PHYSICS · Mechanical Properties of Solids
A load of \(1 \mathrm{~kg}\) weight is a attached to one end of a steel wire of area of cross-section \(3 \mathrm{~mm}^2\) and Young's modulus \(10^{11} \mathrm{~N} / \mathrm{m}^2\). The other end is suspended vertically from a hook on a wall, then the load is pulled horizontally and released. When the load passes through its lowest position the fractional change in length is \(\left(g=10 \mathrm{~m} / \mathrm{s}^2\right)\)
- A \(0.3 \times 10^{-4}\)
- B \(0.3 \times 10^{-3}\)
- C \(0.3 \times 10^{3}\)
- D \(0.3 \times 10^{4}\)
Answer & Solution
Correct Answer
(A) \(0.3 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} Y & =\frac{m g l}{A \Delta l} \\ \Rightarrow \quad \frac{\Delta l}{l} & =\frac{m g}{A Y}\end{aligned}\) \(\begin{aligned} \therefore \quad \frac{\Delta l}{l} & =\frac{1 \times 10}{3 \times 10^{-6} \times 10^{11}} \\ & =0.3 \times 10^{-4}\end{aligned}\)
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