AP EAMCET · Maths · Probability
A person is known to speak the truth in 3 out of 4 occasions. If he throws a die and reports that it is six, then the probability that it is actually six is
- A \(\frac{3}{8}\)
- B \(\frac{2}{7}\)
- C \(\frac{1}{9}\)
- D \(\frac{4}{5}\)
Answer & Solution
Correct Answer
(A) \(\frac{3}{8}\)
Step-by-step Solution
Detailed explanation
\(P(\text{six}) = \frac{1}{6}\) \(P(\text{not six}) = \frac{5}{6}\) \(P(\text{reports six}|\text{is six}) = \frac{3}{4}\) \(P(\text{reports six}|\text{is not six}) = \frac{1}{4}\)…
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