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AP EAMCET · PHYSICS · Thermal Properties of Matter

The amount of heat needed to heat 200 grams of ice at \(-10^{\circ} \mathrm{C}\) to convert it into water at \(30^{\circ} \mathrm{C}\) is
Specific heat capacity of ice \(=2100 \mathrm{~J} \mathrm{~kg}^{-1} \mathrm{~K}^{-1}\)
Specific heat capacity of water \(=4186 \mathrm{~J} \mathrm{~kg}^{-1} \mathrm{~K}^{-1}\)
Latent heat of fusion of ice \(=3.35 \times 10^5 \mathrm{~J} \mathrm{~kg}^{-1}\)

  1. A \(96316 \mathrm{~J}\)
  2. B \(67000 \mathrm{~J}\)
  3. C \(92116 \mathrm{~J}\)
  4. D \(71200 \mathrm{~T}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(96316 \mathrm{~J}\)

Step-by-step Solution

Detailed explanation

We have \(\Delta \mathrm{Q}=\mathrm{mS}_{\mathrm{i}}\left[-10^{\circ}-0^{\circ}\right]-\mathrm{mL}_{\mathrm{f}}+\mathrm{mS}_{\mathrm{w}}\left[0^{\circ}-30^{\circ}\right]\)…