AP EAMCET · Chemistry · Structure of Atom
Total number of angular nodes of orbitals associated with third shell \((n=3)\) of an atom is
- A \(3\)
- B \(4\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
Total number of angular nodes \(=l\), for a given orbital. For \(n=3\), there will be three subshells having \(3 \mathrm{~s}\), \(3 \mathrm{p}\) and \(3 \mathrm{~d}\) orbitals. For \(3 \mathrm{~s}, l=0\), so zero angular nodes. For \(3 \mathrm{p}, l=1\), so one angular nodes.…
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