AP EAMCET · Maths · Circle
The angle subtended by the chord \(x+y-1=0\) of the circle \(x^2+y^2=1\) at the origin is
- A \(\cos ^{-1}\left(\frac{6}{\sqrt{34}}\right)\)
- B \(\frac{\pi}{2}\)
- C \(\cos ^{-1}\left(\frac{2}{\sqrt{13}}\right)\)
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
To find the angle subtended by the chord \(x+y=1\) at the center of the circle \(x^2+y^2=1\), we can follow these steps: Step 1: Identify the Circle and Chord: The given circle is \(x^2+y^2=1\), which has its center at the origin \((0,0)\) and a radius of 1 . The chord is given…
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