AP EAMCET · PHYSICS · Atomic Physics
The difference between the radii of \(n^{\text {th }}\) and \((n+1)^{\text {th }}\) orbits of hydrogen atom is equal to the radius of \((n-1)^{\text {th }}\) orbit of hydrogen. The angular momentum of the electron in the \(n^{\text {th }}\) orbit is _________ ( \(h\) is Planck's constant).
- A \(\frac{h}{\pi}\)
- B \(\frac{2h}{\pi}\)
- C \(\frac{3h}{\pi}\)
- D \(\frac{4h}{\pi}\)
Answer & Solution
Correct Answer
(B) \(\frac{2h}{\pi}\)
Step-by-step Solution
Detailed explanation
(b) Radius of \(n^{\text {th }}\) orbit in an atom, \(r_n=\frac{n^2 h^2}{4 \pi^2 m Z e^2}\) So, \(r_n \propto n^2\) Given in question, difference between radii of \((n+1)^{\text {th }}\) and \(n^{\text {th }}\) orbit \(=\) radius of \(n^{\text {th }}\) orbit.…
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