AP EAMCET · PHYSICS · Electromagnetic Waves
Match the following List-I with List-II.
\(\begin{array}{cccc}
\hline & \text { List-I } & & \text { List-II } \\
\hline \text { A. } & \oint E d A & \text { (i) } & 0 \\
\hline \text { B. } & \oint B d A & \text { (ii) } & -\frac{d \phi_B}{d t} \\
\hline \text { C. } & \oint E d l & \text { (iii) } & \frac{Q}{E_0} \\
\hline \text { D. } & \oint B d l & \text { (iv) } & \mu_0\left(i_c+i_d\right)
\end{array}\)
- A \(\begin{array}{cccc} \text { A } & \text { B } & \text { C } & \text { D } \\ \text { (iii) } & \text { (ii) } & \text { (i) } & \text { (iv) }\end{array}\)
- B \(\begin{array}{cccc} \text { A } & \text { B } & \text { C } & \text { D } \\ \text { (iv) } & \text { (i) } & \text { (iii) } & \text { (ii) } \end{array}\)
- C \(\begin{array}{cccc} \text { A } & \text { B } & \text { C } & \text { D } \\ \text { (iii) } & \text { (i) } & \text { (ii) } & \text { (iv) }\end{array}\)
- D \(\begin{array}{cccc} \text { A } & \text { B } & \text { C } & \text { D } \\ \text { (iii) } & \text { (i) } & \text { (iv) } & \text { (ii) } \end{array}\)
Answer & Solution
Correct Answer
(C) \(\begin{array}{cccc} \text { A } & \text { B } & \text { C } & \text { D } \\ \text { (iii) } & \text { (i) } & \text { (ii) } & \text { (iv) }\end{array}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{A} \rightarrow\) III According to Gauss's law, total electric flux passing through a closed surface is equal to \(\frac{1}{\varepsilon_0}\) times the total charge enclosed within the surface. i.e., \(\quad \phi=\oint \mathbf{E}. d \mathbf{A}=\frac{Q}{\varepsilon_0}\)…
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