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AP EAMCET · PHYSICS · Motion In Two Dimensions

A projectile with speed 50 m s-1 is thrown at an angle of 60° with the horizontal. The maximum height that can be reached is,
(acceleration due to gravity =10 m s-2)

  1. A 90.75 m
  2. B 70.00 m
  3. C 85.00 m
  4. D 93.75 m
Verified Solution

Answer & Solution

Correct Answer

(D) 93.75 m

Step-by-step Solution

Detailed explanation

Maximum height of the projectile is given by, H=u2sinθ22g. Given: u=50 m s-1 & θ=60°. H=502sin60°22×10=2500×32220=93.75 m
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