AP EAMCET · PHYSICS · Motion In Two Dimensions
One second after projection, a projectile is travelling in a direction inclined at \(45^{\circ}\) to horizontal. After two more seconds it is travelling horizontally. Then the magnitude of velocity of the projectile is \(\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)
- A \(10 \sqrt{13} \mathrm{~ms}^{-1}\)
- B \(11 \mathrm{~ms}^{-1}\)
- C \(10 \sqrt{2} \mathrm{~ms}^{-1}\)
- D \(20 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(A) \(10 \sqrt{13} \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
When projectile travels horizontally, then \(t=\frac{T}{2}\) \(\therefore \frac{\mathrm{T}}{2}=3 \Rightarrow \frac{\mathrm{u} \sin \theta}{\mathrm{~g}}=3\) \(\mathrm{u}, \mathrm{u} \sin \theta=30\) After time,…
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