AP EAMCET · Maths · Heights and Distances
An aeroplane flying with uniform speed horizontally one \(\mathrm{km}\) above the ground is observed at an elevation of \(60^{\circ}\). After \(10 \mathrm{~s}\) if the elevation is observed to be \(30^{\circ}\), then the speed of the plane (in \(\mathrm{km} / \mathrm{h}\) ) is
- A \(\frac{240}{\sqrt{3}}\)
- B \(200 \sqrt{3}\)
- C \(240 \sqrt{3}\)
- D \(\frac{120}{\sqrt{3}}\)
Answer & Solution
Correct Answer
(C) \(240 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{llll} \tan 60^{\circ} & =\frac{D P}{A P} \\ \Rightarrow \sqrt{3} & =\frac{1}{A P} \\ \Rightarrow A P & =\frac{1}{\sqrt{3}} & {[\because E Q=D P=1]} \end{array}\) In \(\Delta E A Q\),…
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