AP EAMCET · PHYSICS · Motion In Two Dimensions
A bowling machine placed at a height \(h\) above the earth surface releases different balls with different angles but with same velocity \(10 \sqrt{3} \mathrm{~ms}^{-1}\). All these balls landing velocities make angles \(30^{\circ}\) or more with horizontal. Then the height ' h ' (in meters) (acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A 15
- B 12
- C 10
- D 5
Answer & Solution
Correct Answer
(D) 5
Step-by-step Solution
Detailed explanation
\begin{aligned} & u_x=v_x=10 \sqrt{3} m s^{-1} \\ & t=\sqrt{\frac{2 h}{g}} \\ & \therefore v_y=u_y+g t=0+g \sqrt{\frac{2 h}{g}} \\ & \therefore \tan 30^{\circ}=\frac{v_y}{v_x}=\frac{g \sqrt{\frac{2 h}{g}}}{10 \sqrt{3}}=\frac{\sqrt{2 g h}}{10 \sqrt{3}} \\ & \therefore \quad h=5…
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