AP EAMCET · PHYSICS · Thermodynamics
A work of \(166.28 \mathrm{~J}\) is done to adiabatically compress one mole of a gas. If the increase in the temperature of the gas is \(8^{\circ} \mathrm{C}\), the gas is
\(\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)\)
- A monatomic
- B diatomic
- C polyatomic
- D mixture of diatomic and polyatomic
Answer & Solution
Correct Answer
(B) diatomic
Step-by-step Solution
Detailed explanation
Work done on the system, \(\mathrm{W}=166.28 \mathrm{~J}\) Increase in temperature, \(\Delta \mathrm{T}=\mathrm{T}_2-\mathrm{T}_1=8^{\circ} \mathrm{C}\) Work done in adiabatic process,…
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