AP EAMCET · Maths · Binomial Theorem
If the \(2^{\text {nd }}, 3^{\text {rd }}\) and \(4^{\text {th }}\) terms in the expansion of \((x+a)^{\mathrm{n}}\) are \(96,216,216\) respectively and \(n\) is a positive integer then \(a+x=\)
- A \(n+1\)
- B \(n\)
- C \(n-1\)
- D \(\frac{n}{2}\)
Answer & Solution
Correct Answer
(A) \(n+1\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & { }^n C_1 x^{n-1} a=96 ....(i)\\ & { }^n C_2 x^{n-2} a^2=216 ....(ii)\\ & { }^n C_3 x^{n-3} a^3=216 .....(iii) \end{aligned}\) (i) \(\div\) (ii) we get,…
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