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AP EAMCET · Maths · Probability

\(A\) and \(B\) are two independent events of a random experiment and \(P(A)>P(B)\).
If the probability that both \(A\) and \(B\) occur is \(\frac{1}{6}\) and neither of them occurs is \(\frac{1}{3}\), then the probability of the occurance of \(B\) is

  1. A \(\frac{1}{4}\)
  2. B \(\frac{1}{3}\)
  3. C \(\frac{1}{2}\)
  4. D \(\frac{3}{8}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{3}\)

Step-by-step Solution

Detailed explanation

\(P(A)P(B) = \frac{1}{6}\) \((1-P(A))(1-P(B)) = \frac{1}{3}\) \(1 - (P(A)+P(B)) + P(A)P(B) = \frac{1}{3}\) \(1 - (P(A)+P(B)) + \frac{1}{6} = \frac{1}{3}\) \(P(A)+P(B) = 1 + \frac{1}{6} - \frac{1}{3} = \frac{6+1-2}{6} = \frac{5}{6}\) Let \(P(A)\) and \(P(B)\) be roots of…